Well, Define M as ABC and N as XYZ. A,B,C,X,Y,Z are binary numbers.
Now, ABC(XOR)XYZ = 110. This means, C=Z, A!=X and B!=Y.
M*M = ABC * ABC and N*N = XYC *XYC and (ABC*ABC)(XOR)(XYC*XYC) = 10110
Try to calculate M*M and N*N in terms of ABC and XYZ.
Last digits are C*C and C*C. There is no...