Recent content by Otropablo

You are all right. It hited me after few hours of trying with a simulator. Thanks a lot for taking the time to read my wrong calculations. I promess to take more analisys before posting!

Please correct me on this: Check on host's logic, when he has to choose between 2 doors and when he doesn't has to. Car is behind A. P(win) = P(1/3 Ben chooses A, 1/2 host shows C, 1/2 Ben stays) + P( 1/3 Ben chooses A, 1/2 host shows B, 1/2 Ben stays) + P(1/3 Ben chooses B, 1/1 host shows...

I think you'll be amazed. I've read many so called demostrations for this issue in Physics Help and Math Help - Physics Forums and everyone is wrong, since they are giving 1/3 chances to loose in the first election, wich never happens

You do know wich door the host will open: one with a goat. The chances of winning aren't envolved in the first choice, since there's 0% chance (no matter wich door you choose) that the first door the hosts opens has the car. At the end of the day, you'll choose between 2 doors: One you already...

Hi there!. You are always assuming that you have 1/3 of chances to win because it's 3 doors. But according to game's rules: you are always 1/2 chances to win. These are the actual rules: 1) You are going to choose between 3 doors 2) Host is going to open a door (but not the one you've choose...