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Swing Conservation of energy: mgL=2mg(L-h) L=2L-2H 2H=L H=(L/2)

Ah. You are correct sir. I mis-interpreted the question and hence your equation. I assumed the hour hand was exactly on the 5 when the time is 5:15...stupid mistake. If i compensate for the fact that the hour hand is 1/4 of the way between the 5 and the 6 at 5:15. the "initial seperation"...

Bowling Ball I couldn’t find the original thread but i have an attempt at the solution to the bowling ball question. The scenario was 1 ball had varying density and the second ball had constant density. how to determine which ball is which. The poster said we could assume the density varies...

Clock If i'm not mistaken this would give time=5.4545 = 5:27:16 I solved it using rates and ratios. This approach worked for Andy's original clock problem. Distance traveled by minute hand = distance traveled by hour hand +initial separation. Let RHH= rate hour hand=(1/(12*60*60))=1/43200...