7.7 Deck of Pokers

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5/27/11
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A deck of pokers. Three choices: A: 26 black, 26 Red; B: 13 black, 13 Red; C: random 26 card from the deck. Take the first two cards, if same color, the win $1, otherwise lose $1. Which deck is best for you if you are playing? Why? How to do simulations? How to draw the random pile of 26 cards?


I did solve the problem but its hard to compare all those probability numbers without doing all the calculations.
Anyone knows how to compare the three probabilities with minimal calculations?
 
Without any calculation I would say that the answer is C since there is an higher probability that it will be unbalanced, i.e. you will a have greater probability to take two cards of the same colour. This is just my intuition.
 
B is the best at 13/25. If you're drawing 2 random from a random sample w/o replacement, then you are just taking 2 random from the whole population, so A and C are the same at 26/51.
 
B is the best at 13/25. If you're drawing 2 random from a random sample w/o replacement, then you are just taking 2 random from the whole population, so A and C are the same at 26/51.
Shouldn't those numbers be for B: 12/25 and A & C: 25/51. Am I missing something?
 
Choose A, you win with 26/52* 25/51, Choose B, you win with 13/26*12/25. 26/52 = 25/52 = 1/2, but 25/51 > 12/25. So, A will give you a better winning odds. C is equivalent to A, you can argue this by Total Probability Theorem.
 
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