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I don't quite agree.If (x_1) is the length of the first portion broken off, and (x_2), the length of the second portion, to form a triangle, we need (x_1<0.5)and (0.5<x_1+x_2><1)i.e.</x_1+x_2>(x_2) between (0.5-x_1) and (1-x_1)<x_1+x_2><x_2><x_2><x_2>(\int_0^{\frac{1}{2}}{\int_{\frac{1}{2}-x_1}^{1-x_1}\frac{x_1}{1}*\frac{x_2}{1-x_1}dx_2 dx_1)Integrating, I got 0.2017</x_2></x_2></x_2></x_1+x_2>
I don't quite agree.
If (x_1) is the length of the first portion broken off, and (x_2), the length of the second portion, to form a triangle, we need (x_1<0.5)and (0.5<x_1+x_2><1)
i.e.</x_1+x_2>(x_2) between (0.5-x_1) and (1-x_1)<x_1+x_2><x_2><x_2><x_2>
(\int_0^{\frac{1}{2}}{\int_{\frac{1}{2}-x_1}^{1-x_1}\frac{x_1}{1}*\frac{x_2}{1-x_1}dx_2 dx_1)
Integrating, I got 0.2017
</x_2></x_2></x_2></x_1+x_2>
